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It is often the case in MOO programming that you will want to access the elements of a list individually, with each element stored in a separate variables. This desire arises, for example, at the beginning of almost every MOO verb, since the arguments to all verbs are delivered all bunched together in a single list. In such circumstances, you could write statements like these:
first = args[1]; second = args[2]; if (length(args) > 2) third = args[3]; else third = 0; endif |
This approach gets pretty tedious, both to read and to write, and it's prone to errors if you mistype one of the indices. Also, you often want to check whether or not any extra list elements were present, adding to the tedium.
MOO provides a special kind of assignment expression, called scattering assignment made just for cases such as these. A scattering assignment expression looks like this:
{target, ...} = expr |
where each target describes a place to store elements of the list that results from evaluating expr. A target has one of the following forms:
variable
?variable
?variable = default-expr
@variable
@
syntax in list construction, this variable is
assigned a list of all of the `leftover' list elements in this part of the list
after all of the other targets have been filled in. It is assigned the empty
list if there aren't any elements left over. This is called a rest
target, since it gets the rest of the elements. There may be at most one rest
target in each scattering assignment expression.
If there aren't enough list elements to fill all of the required targets, or if
there are more than enough to fill all of the required and optional targets but
there isn't a rest target to take the leftover ones, then E_ARGS
is
raised.
Here are some examples of how this works. Assume first that the verb
me:foo()
contains the following code:
b = c = e = 17; {a, ?b, ?c = 8, @d, ?e = 9, f} = args; return {a, b, c, d, e, f}; |
Then the following calls return the given values:
me:foo(1) error--> E_ARGS me:foo(1, 2) => {1, 17, 8, {}, 9, 2} me:foo(1, 2, 3) => {1, 2, 8, {}, 9, 3} me:foo(1, 2, 3, 4) => {1, 2, 3, {}, 9, 4} me:foo(1, 2, 3, 4, 5) => {1, 2, 3, {}, 4, 5} me:foo(1, 2, 3, 4, 5, 6) => {1, 2, 3, {4}, 5, 6} me:foo(1, 2, 3, 4, 5, 6, 7) => {1, 2, 3, {4, 5}, 6, 7} me:foo(1, 2, 3, 4, 5, 6, 7, 8) => {1, 2, 3, {4, 5, 6}, 7, 8} |
Using scattering assignment, the example at the begining of this section could be rewritten more simply, reliably, and readably:
{first, second, ?third = 0} = args; |
It is good MOO programming style to use a scattering assignment at the top of nearly every verb, since it shows so clearly just what kinds of arguments the verb expects.
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